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5n^2-65=12n
We move all terms to the left:
5n^2-65-(12n)=0
a = 5; b = -12; c = -65;
Δ = b2-4ac
Δ = -122-4·5·(-65)
Δ = 1444
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1444}=38$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-38}{2*5}=\frac{-26}{10} =-2+3/5 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+38}{2*5}=\frac{50}{10} =5 $
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